Reference · Vectors

vec.sqrt

vec.sqrt(list) -> list

What it does

The square root of each item, as a list of floats. Ints come back as floats too: vec.sqrt([4]) is [2.0].

Examples

print(vec.sqrt([1, 4, 9]))print(vec.sqrt([2, 0.25]))

[1.0, 2.0, 3.0][1.4142135623730951, 0.5]

Edge cases

• A negative item gives NaN, not an error, unlike math.sqrt(-1).
• 0 gives 0.0; inf gives inf.
• The empty list, or null, gives the empty list.

print(vec.sqrt([-1, 0]))print(vec.sqrt([math.inf]))print(vec.sqrt([]), vec.sqrt(null))

[NaN, 0.0][inf][] []

Errors

An item that is not an int or a float, or an argument that is not a list, is a runtime error, not an error value.

print(vec.sqrt(3))

line 1: `vec.sqrt` expects a list as argument 1, got int

Chaining

The root mean square of a list, and the lengths of several vectors at once:

let xs = [3, 4, 12]print(xs | vec.pow(2) | stats.mean | math.sqrt)print([[3, 4], [5, 12]] | map((v) => vec.dot(v, v)) | vec.sqrt)

7.505553499465135[5.0, 13.0]

See also

vec.pow, vec.exp, vec.log, math.sqrt, sqrt

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