Reference · Vectors

vec.exp

signature

vec.exp(list) -> list

What it does

e raised to each item, as a list of floats. It undoes vec.log, up to float rounding.

print(vec.exp([0, 1, 2]))print(vec.exp(vec.log([2, 10])))

output

[1.0, 2.718281828459045, 7.38905609893065][2.0, 10.000000000000002]

A large item overflows to inf, not an error, unlike math.exp(1000); a very negative one underflows to 0.0.
The empty list, or null, gives the empty list.

print(vec.exp([1000, -1000]))print(vec.exp([]), vec.exp(null))

output

[inf, 0.0][] []

An item that is not an int or a float, or an argument that is not a list, is a runtime error, not an error value.

this one fails

print(vec.exp([1, true]))

output

line 1: `vec.exp` expects a list of numbers, but item 1 is bool

A softmax: exponentials scaled to sum to 1.

let z = [1, 2, 3]let e = z | vec.sub(max(z)) | vec.expprint(e | vec.div(sum(e)) | vec.round(3))

output

[0.09, 0.245, 0.665]

On vec.exp(): questions, tips, corrections, and code that uses it.

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